After messing with it I figured out a way to do it, but I don't know if there is an easier way or if I can even explain this right.
Each mouseover event for each link needs to be differentiated somehow. The MouseOver() event you have right now changes all the images. Instead create seperate mouseover events for each link. Like this:
CODE
function mouseOver1()
{
document.home.src ="http://lucasites.vndv.com/nav1hover.png"
}
function mouseOver2()
{
document.temp.src ="http://lucasites.vndv.com/nav2hover.png"
}
function mouseOver3()
{
document.port.src ="http://lucasites.vndv.com/nav3hover.png"
}
function mouseOver4()
{
document.serv.src ="http://lucasites.vndv.com/nav4hover.png"
}
Then in each image code call the corresponding mouseOver event.
Like so:
CODE
<div class="navigation">
<img src="http://lucasites.vndv.com/nav0.png" border="0"><a href="home.html"><img
border="0" alt="Home" src="http://lucasites.vndv.com/nav1.png" name="home" width="128"
height="35" onmouseover="mouseOver1()" onmouseout="mouseOut()" onmousedown="mouseDown()" /></a><a
href="templates.html"><img
border="0" alt="Templates" src="http://lucasites.vndv.com/nav2.png" name="temp" width="128"
height="35" onmouseover="mouseOver2()" onmouseout="mouseOut()" onmousedown="mouseDown()" /></a><a
href="portfolio.html"><img
border="0" alt="Portfolio" src="http://lucasites.vndv.com/nav3.png" name="port" width="128"
height="35" onmouseover="mouseOver3()" onmouseout="mouseOut()" onmousedown="mouseDown()" /></a><a
href="services.html"><img
border="0" alt="Services" src="http://lucasites.vndv.com/nav4.png" name="serv" width="129"
height="35" onmouseover="mouseOver4()" onmouseout="mouseOut()" onmousedown="mouseDown()" /></a><img
src="http://lucasites.vndv.com/nav5.png" border="0">
</div>